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If costheta = 3/4, find the value of sin2theta

pls help me

cosθ\theta = 34\frac 34

sin2θsin2\theta = 2sinθ×cosθ2sin\theta \times cos\theta = 2sinθ×342sin\theta \times \frac 34 --- (i)

sin2θsin^2 \theta = 1 - cos2θcos^2 \theta

sinθsin \theta = 1(34)2\sqrt{1 - (\frac 34)^2} = 74\frac {\sqrt7}{4}

From (i),
sin2θsin2\theta = 378\frac{3\sqrt7}{8}

dibas answered a year ago